162 lines
7.8 KiB
Plaintext
162 lines
7.8 KiB
Plaintext
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Episode: 4382
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Title: HPR4382: Understanding Antenna Gain and the Decibel scale
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Source: https://hub.hackerpublicradio.org/ccdn.php?filename=/eps/hpr4382/hpr4382.mp3
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Transcribed: 2025-10-26 00:01:55
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---
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This is Hacker Public Radio episode 4382,
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produced at the 20th of May 2025.
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Today's show is entitled,
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Understanding in 10 Again and the Decable Scale,
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is part of the series HAM Radio.
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It is hosted by Paul J and is about 8 minutes long.
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It carries a clean flag.
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The summary is,
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the use of decibels can be a bit confusing.
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So in this episode, Paul will enlighten you.
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Good day, everyone.
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This is Paul J and I'd like to give you a quick show about decibels and antenna gain.
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So, why am I doing this?
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I'm working towards getting my full licence for amateur radio in the UK.
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I decided it would be a good idea to review the training material available for the foundation,
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intermediate and full licence.
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Even though I had the foundation licence already,
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I wanted to go back and really confirm my understanding.
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Now, one aspect that I find,
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I kind of understand,
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but never really properly understood, is decibels.
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So, when you read the book about decibels,
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it doesn't really go into much detail about
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how they calculated or how to use them.
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It just says,
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well, you need to know that
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three decibels is double-layer gain
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and ten decibels is ten times the gain.
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So as part of this activity,
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I've actually now gone into the maths behind it to understand
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and really clarify my own head how it works.
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The formula for power in decibels
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is ten times log to the base of ten of P,
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where P is the power in watts.
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Now, the base reference is one watt.
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So, one watt is actually zero decibels.
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When we look at antenna gain,
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we look at the amount of power output relative to this one watt.
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So, if we start with two watts,
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then the power in decibels will be ten times log ten of two.
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This is a fraction over three.
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So, if you go back to my original comment
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about three being double the power,
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so two watts is double-one watt
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and ten the log ten of two is three.
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And similarly, if you were to take log ten of ten,
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then it's one, so ten times one would be ten.
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So, this is how we have ten times.
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So, this is really straightforward.
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Now, the next unit that you will see
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in amateur radio is dBm,
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or decibels relative to a milli watt.
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So, it's the same formula again.
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Except this time, we take one milli watt as zero decibels.
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And we can then reference the power to this one milli watt.
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So, one watt is equal to one thousand milli watts.
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Log to the base ten of a thousand times ten
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would be thirty dBm.
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So, this is another figure you often see.
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Thirty dBm is equal to zero dB.
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The next unit that you will see is dBm,
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which is decibels relative to an isotropic antenna.
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Now, the gain of an isotropic antenna is one.
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And therefore, gain of ten dB would be again of ten dBm.
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The next unit of reference is dBd,
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which is decibels of gain relative to a standard half wave dipole antenna.
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Now, the gain of a half wave dipole antenna is 2.15 dBm.
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So, 2.15 decibels relative to an isotropic antenna.
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So, 2.15 dBm is equal to zero dBd.
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So, an antenna with a gain of ten dBm is equal to ten dB,
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and is therefore equal to seven point eight five dBd.
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Because the decibel scale is logarithmic,
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it means that you can add the decibel values together
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to understand the gain or losses through a full circuit.
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You haven't got to multiply the numbers together.
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So, to get from dB to dBd,
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you can simply subtract 2.15.
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So, ten dBm is equal to seven point eight five dBd.
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Okay, so now I like to talk about effective radiated power.
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So, if we check the page in Wikipedia, it says this.
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Effective radiated power is the standard definition of direct...
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of directional radio frequency power,
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such as that emitted by a radio transmitter.
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It is the total power in watts that would have to be radiated by a half wave dipole antenna
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to give the same radiation intensity as the actual source antenna
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at a distant receiver located in the direction of the antenna's strongest beam.
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If we use an isotropic antenna instead of a dipole,
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then we get the value of ERP,
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which is the effective isotropic radiated power.
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You'll not be surprised to hear that the relationship between ERP and ERP
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is fairly easily calculated.
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So, if we use decibels,
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then ERP is equal to the ERP plus 2.15 decibels.
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So, 2.15 decibels reflects the gain of a dipole antenna.
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If we take watts, ERP and watts is equal to ERP and watts multiplied by 1.64,
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which is the power gain of the dipole antenna.
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Let us look at a practical application of these values.
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My KX3 transmitter has a maximum power of 15 watts.
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This is 11.77 dB when I put the numbers through the formula we discussed at the beginning.
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I now connect my transmitter to a Yagi Uda antenna with a gain of 10 dB.
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So, this is 10 times the gain of a half wave dipole.
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We can now add those two numbers together.
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So, 11.77 plus 10 would give us 21.77 dB.
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And if we then look at the conversing that back to watts,
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this will give us 150.3 watts of ERP.
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So, what does that mean?
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So, that means that if I had a dipole antenna to achieve the same signal strength in the direction that I am pointing my antenna,
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I would have to input 150 watts into that antenna.
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So, clearly from my 15 watt KX3, that is quite a good result.
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Now, if I want to calculate that number as ERP,
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then this would be adding the 2.15 value.
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So, another of the 21.77 would give us 23.918.
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And if we convert this back to watts,
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then this would give us 246 watts of ERP.
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So, in other words, we would have to feed 246 watts into an isotropic antenna
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in order to get the same signal strength in the direction I am pointing my antenna in.
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Now, clearly the isotropic antenna is a theoretical thing,
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dipole isn't, but it just goes to show that you can achieve a lot more with antennas in terms of power outputs
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than you can just by increasing the power on the transmitter alone.
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So, I hope that's been a useful round tour of decibels and how to use decibels and look at antenna performance.
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If your mind works like mine,
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I really recommend you get a calculator out and use the formula
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and just calculate back and forth from decibels to watts or millawatts
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and just try and understand how the numbers feel.
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This helped me understand more clearly how this all fits together.
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If you consider studying to become a radiometer,
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I strongly recommend it, it's not difficult to do.
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Particularly, if I take the UK example at foundation level,
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the coursework is fairly straightforward
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and the exam is a multiple choice.
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So, you can work to get through this and if you have a local radio club,
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I definitely recommend you go and join them.
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But to be fair, I did it during lockdown when that option wasn't available.
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So, yeah, become a radiometer, you'll find it good fun
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and it might be useful and expand your interests in other areas as well.
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So, that concludes this particular episode of Hacker Public Radio.
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If I've got anything wrong, I will come back and make another show to correct it.
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But I think now I have actually got everything in this show correct.
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Even though I did have to go back and record the EIRP and EIRP section again
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because I had made some mistakes.
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I think it just goes to show that if you really want to understand something,
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try to explain it to somebody else.
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Anyway, I look forward to seeing your comments in the show notes
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and I look forward to making another episode at some point in the future.
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So, this is Paul J signing off for Hacker Public Radio.
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You have been listening to Hacker Public Radio at Hacker Public Radio does work.
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Today's show was contributed by a HBR listener like yourself.
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If you ever thought of recording a podcast,
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then click on our contribute link to find out how easy it really is.
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Hosting for HBR has been kindly provided by
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an onesthost.com,
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the Internet Archive and R-Sync.net.
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On the Sadois status, today's show is released on our Creative Commons
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Attribution 4.0 International License.
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